计算器的加减乘除应用

发表于 2022-2-22 22:44:01

#include<reg52.h>

sbit ENLED=P1^1;

sbit P20=P2^0;
sbit P21=P2^1;
sbit P22=P2^2;
sbit P23=P2^3;
sbit kout1=P2^4;
sbit kout2=P2^5;
sbit kout3=P2^6;
sbit kout4=P2^7;

unsigned char ledchar[]={
0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,
0x80,0x90,0x88,0x83,0xC6,0xA1,0x86,0x8E,
};
unsigned char keysta[4][4]={
{1,1,1,1},{1,1,1,1},{1,1,1,1},{1,1,1,1}
};
unsigned char ledbuff[6]={
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
};
unsigned char keycodeMap[4][4]={
  {0x31,0x32,0x33,0x26},          //êy×Ö¼ü1￡»êy×Ö¼ü2￡»êy×Ö¼ü3￡»ÏòéÏ ¼ó
{0x34,0x35,0x36,0x25},          //êy×Ö¼ü4￡»êy×Ö¼ü5￡»êy×Ö¼ü6￡»Ïò×ó ¼õ
{0x37,0x38,0x39,0x28},          //êy×Ö¼ü7￡»êy×Ö¼ü8￡»êy×Ö¼ü9￡»ÏòÏÂ 3Ë
{0x30,0x1B,0x0D,0x27}             //êy×Ö¼ü0￡»ESC¼ü￡»»Ø3μ¼ü￡» Ïòóò 3y
};

void keydrive();
void keyaction(unsigned char keycode);
void shownumber(unsigned long num);

void main ()
{

ENLED=0;
  EA=1;
  TMOD=0x01;
  TH0=0xFE;
  TL0=0xEF;
  TR0=1;             //′ò¿a¶¨ê±Æ÷
  ET0=1;             //′ò¿aÖD¶Ï
ledbuff[0]=ledchar[0];

while(1)
{
keydrive();
}
}
void shownumber(unsigned long num)
{
unsigned char buf[6];
signed int i;
for(i=0;i<6;i++)
{
buf[i]=num%10;
num=num/10;
}
for(i=5;i>=1;i--)
{
if(buf[i]==0)
{
ledbuff[i]=0xFF;
}
else
break;
}
for(;i>=0;i--)
{
ledbuff[i]=ledchar[buf[i]];
}
}

void keyaction(unsigned char keycode)
{
static signed long result=0;
static signed long addend=0;
static unsigned char i=0;//óÃóúÅD¶ÏoÎÖÖÔËËã

if((keycode>=0x30)&&(keycode<=0x39))//êäèëêy×Ö
{
addend=(addend*10)+(keycode-0x30);
shownumber(addend);
}
else if(keycode==0x26)//¼ó·¨¼ü
{ i=1;
result+=addend;
addend=0;
shownumber(addend);

}
else if(keycode==0x25)//¼õ·¨¼ü
{ i=2;
   result-=addend;
addend=0;
shownumber(addend);
  }
  else if(keycode==0x28)//3Ë·¨¼ü
{ i=3;
if(result==0)       //Ôú½øDDá¬DøÔËËãê±ÅD¶ÏÔËËãDÎê½
{result=addend;    //èç1ûresult￡¡=0￡¬3D½óéÏ′ÎÔËËã½á1û
addend=0;
shownumber(addend);
}
else
{shownumber(addend);}
}
else if(keycode==0x27)//3y·¨¼ü
{ i=4;
if(result==0) //Ôú½øDDá¬DøÔËËãê±ÅD¶ÏÔËËãDÎê½
{ result=addend; //í¬éÏ
addend=0;
shownumber(addend);
}
else
{shownumber(addend);}
}
else if(keycode==0x0D)//»Ø3μ¼ü
{ switch(i)
{
case 1: result+=addend;addend=0;shownumber(result);break;
case 2: result-=addend;addend=0;shownumber(result);break;
case 3: result*=addend;addend=0;shownumber(result);break;
case 4: result/=addend;addend=0;shownumber(result);break;
default:break;
}

}
else if(keycode==0x1B)//ESC¼ü
{
addend=0;
result=0;
shownumber(result);
}
}

void keydrive()
{
unsigned int i,j;                         //iêÇDD￡¬jêÇáD
static unsigned char backup[4][4]={
{1,1,1,1},{1,1,1,1},{1,1,1,1},{1,1,1,1}
  };

for(i=0;i<4;i++)
{
for(j=0;j<4;j++)
{
if(keysta[i][j]!=backup[i][j])
{
if(backup[i][j]==0)
{
keyaction(keycodeMap[i][j]);
}
backup[i][j]=keysta[i][j];
}
}
}
}

void ledscan()
{
static unsigned int i=0;
P0=0xFF;
if(i==0)
{P20=1

21=0

22=1;i++

0=ledbuff[0];}
else if(i==1)
{P20=0

21=0

22=1;i++

0=ledbuff[1];}
else if(i==2)
{P20=1

21=1

22=0;i++

0=ledbuff[2];}
else if(i==3)
{P20=0

21=1;P22=0;i++;P0=ledbuff[3];}
else if(i==4)
{P20=1;P21=0;P22=0;i++;P0=ledbuff[4];}
else if(i==5)
{P20=0;P21=0;P22=0;i=0;P0=ledbuff[5];}
}

void keyscan()
{
static unsigned int a=0;
static unsigned char keyout=0;
unsigned char i=0;
static unsigned char keybuf[4][4]={
0xFF,0xFF,0xFF,0xFF,
   0xFF,0xFF,0xFF,0xFF,
   0xFF,0xFF,0xFF,0xFF,
   0xFF,0xFF,0xFF,0xFF
};
P20=1;P21=1;P22=1;P23=1;

keybuf[keyout][0]=(keybuf[keyout][0]<<1)|P20;
keybuf[keyout][1]=(keybuf[keyout][1]<<1)|P21;
keybuf[keyout][2]=(keybuf[keyout][2]<<1)|P22;
keybuf[keyout][3]=(keybuf[keyout][3]<<1)|P23;

for(i=0;i<4;i++)
{
if((keybuf[keyout][i]&0x0F)==0x00)
{
keysta[keyout][i]=0;
}
else if((keybuf[keyout][i]&0x0F)==0x0F)
{
keysta[keyout][i]=1;
}
else{}
}

keyout++;
if(keyout>=4)
{
keyout=0;
}
// keyout=keyout&0x03;
switch(keyout)
{
case 0:kout1=1;kout2=1;kout3=1;kout4=0;break;
case 1:kout1=1;kout2=1;kout3=0;kout4=1;break;
case 2:kout1=1;kout2=0;kout3=1;kout4=1;break;
case 3:kout1=0;kout2=1;kout3=1;kout4=1;break;
default :break;
}
//P20=0;P21=0;P22=0;

P0=0xFF;
if(a==0)
{P20=1;P21=0;P22=1;a++;P0=ledbuff[0];}
else if(a==1)
{P20=0;P21=0;P22=1;a++;P0=ledbuff[1];}
else if(a==2)
{P20=1;P21=1;P22=0;a++;P0=ledbuff[2];}
else if(a==3)
{P20=0;P21=1;P22=0;a++;P0=ledbuff[3];}
else if(a==4)
{P20=1;P21=0;P22=0;a++;P0=ledbuff[4];}
else if(a==5)
{P20=0;P21=0;P22=0;a=0;P0=ledbuff[5];}
}
void interruptTime() interrupt 1
{
TH0=0xFE;
  TL0=0xEF;
ledscan();
keyscan();
}

[寒假笔记] 计算器的加减乘除应用