利用串口显示数字到数码管
程序如下
#include<reg52.h>
sbit ADDR0 = P2^0;
sbit ADDR1 = P2^1;
sbit ADDR2 = P2^2;
sbit ENLED = P1^1;
unsigned char code LedChar[] = {
0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
};
unsigned char LedBuff[7] = {
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
};
unsigned char RxdByte = 0;
unsigned char T0RH = 0;
unsigned char T0RL = 0;
void ConfigTimer0(unsigned int ms);
void ConfigUART(unsigned int baud);
void main()
{
EA = 1;
ENLED = 0;
ConfigTimer0(1);
ConfigUART(9600);
while(1)
{
LedBuff[0] = LedChar[RxdByte & 0x0F];
LedBuff[1] = LedChar[RxdByte>>4];
}
}
void ConfigTimer0(unsigned int ms)
{
unsigned long tmp;
tmp = 32768000/12;
tmp = (tmp*ms)/1000;
tmp = 65536 - tmp;
tmp = tmp + 13;
T0RH = (unsigned char)(tmp>>8);
T0RL = (unsigned char)tmp;
TMOD &= 0xF0;
TMOD |= 0x01;
TH0 = T0RH;
TL0 = T0RL;
ET0 = 1;
TR0 = 1;
}
void ConfigUART(unsigned int baud)
{
SCON = 0x50;
TMOD &= 0x0F;
TMOD |= 0x20;
TH1 = 255-(32768000/12/32)/baud;
TL1 = TH1;
ET1 = 0;
ES = 1;
TR1 = 1;
}
void LedScan()
{
static unsigned char i = 0;
P0 = 0xFF;
switch(i)
{
case 0:ADDR2 = 0;ADDR1 = 0;ADDR0 = 0;i++0 = LedBuff[5];break;
case 1:ADDR2 = 0;ADDR1 = 0;ADDR0 = 1;i++0 = LedBuff[4];break;
case 2:ADDR2 = 0;ADDR1 = 1;ADDR0 = 0;i++0 = LedBuff[3];break;
case 3:ADDR2 = 0;ADDR1 = 1;ADDR0 = 1;i++0 = LedBuff[2];break;
case 4:ADDR2 = 1;ADDR1 = 0;ADDR0 = 0;i++0 = LedBuff[1];break;
case 5:ADDR2 = 1;ADDR1 = 0;ADDR0 = 1;i++0 = LedBuff[0];break;
case 6:ADDR2 = 1;ADDR1 = 1;ADDR0 = 0;i = 00 = LedBuff[6];break;
default: break;
}
}
void InterruptTimer0() interrupt 1
{
TH0 = T0RH;
TR0 = T0RL;
LedScan();
}
void InterruptUART() interrupt 4
{
if(RI)
{
RI = 0;
RxdByte = SBUF;
SBUF = RxdByte;
}
if(TI)
{
TI = 0;
}
}
|